what is the mass of air within a 83602.3 cm3 balloon in grams?
at 75 degrees C
Find the density of air. Note that density p = m/v (note that the Greek character 'rho' is generally used to denote density, it's not actually a p but looks similar). Rearrange the density formula to find the mass based on the density and volume.
density of air = 1.014 g/L
(Where m = mass and v = volume).
it might help if it were true but 1cm^3=1ml not 1 Liter
And that applies to water at 4 degrees celsius
Lol oops my bad.
so how do i find mass?
volume x density?
D= M/v so m =dxv
p = m/v so m = pv Perhaps slightly unrelated, but attached is a list of unit conversions we used in a chemical engineering unit that some may find useful.
can i just multiply g/L by cm3 or do i convert somehow?
So if the volume is constant, why did they give you the temperature?
I'm assuming you're supposed to know/find the density of "air" at 75 degrees Celsius (and assume that "air" is the same universally).
yeah i got the density fine. 1.014 g/L. but do i have to convert my 83602.3 cm3 ?
@mertsj to confuse me?
Keeping it simple, convert either 1.014 g/L to g/cm^3 OR 83602.3 cm^3 to L, depending on which makes the most sense to you (think about which number is larger and what the conversion factor will be). Then multiply.
it needs to be in grams. so 83.6023 liters and then multiply?
83602.3 cm^3=83602.3 ml=83.6023 L|dw:1332474171555:dw|
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