(2x^2+5x-12)/(x^2-4x)

Question

(2x^2+5x-12)/(x^2-4x)<0

anonymous · Answer

Must be 6X

anonymous · Answer

show work?

anonymous · Answer

factor the numerator and denominator:
[(2x-3)*(x+4)] / [x*(x-4)]
....hmm nothing cancels...
btw, what do you want done here?

anonymous · Answer

It is 6x

anonymous · Answer

i think he needs to solve for x.

move the denominator to the other side of the equation, then start solving by using algebra.

The rule to remember when dealing with < or > signs is to FLIP THE SIGN each time you are multiplying or dividing by a negative number.

anonymous · Answer

yea it is solving for x. although i got to the factoring but i was unsure of what to do next

anonymous · Answer

6x

anonymous · Answer

ok, then we need to solve, that is, find all the x-values that will make the stament true...

anonymous · Answer

so after multiplying and doing algebra, you should have x^2 +9x + - 12 <0

anonymous · Answer

from the factored expression [(2x-3)*(x+4)] / [x*(x-4)]
find all x values that will make the numerator = 0 
then all x values that will make the denominator = 0

anonymous · Answer

for numerator:  x = 3/2, -4
for denominator:  x = 0, 4
now pick values within those interval and check what will make f positive or negative:
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