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integrate 2/2x+3
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take the two out so... 2 int (1/2x+3) integral of that is ln (2x+3)/2 so 2 (ln 2x+3)/2 =ln 2x + 3 yes?
no that as to be ln 2x+3/2+C
i get the arbitrary constant...it was a minor mistake...but why is there an over two? when i take the derivative of ln (2x+3) it's exactly 2/(2x+3)
remember ur integrating...there is a rule that suffices that the integral of the 2x must be the denominator
http://www.wolframalpha.com/input/?i=int+2%2F%282x%2B3%29 wolframalpha agrees with me...the question is integral of 2/(2x+3) right?
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