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IIT study group 24 Online
OpenStudy (anonymous):

Cl2 + 2 KOH = KCl + KClO + H2O 3 KClO = 2KCl + KClO3 4 KClO3 = 3KClO4 + KCl How much Cl2 is needed to prepare 400g of KClO4??? in grams Ive got 38.056 gm

OpenStudy (anonymous):

Cl2 + 2 KOH = KCl + KClO + H2O 3 KClO = 2KCl + KClO3 4 KClO3 = 3KClO4 + KCl How much Cl2 is needed to prepare 400g of KClO4??? in grams Ive got 38.056 gm is the crct quest

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