Question

solve the equation, 2y^2 = 5y

confuse with this one.

Answer 1

2y^(2)=5y


2y^(2)-5y=0

Factor out the GCF of y from 2y^(2)-5y.
y(2y-5)=0

Set the single term factor on the left-hand side of the equation equal to 0.
y=0

Set each of the factors of the left-hand side of the equation equal to 0.
2y-5=0

Since -5 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 5 to both sides.
2y=5

Divide each term in the equation by 2.
y=(5)/(2)

The complete solution is the set of the individual solutions.
y=0,(5)/(2)

Answer 2

2y^2 = 5y
2y^2 -5y= 0
y(2y-5) =0
y=0 or 2y-5 =0
y=0 or y=5/2