Michael rolled two number cubes, numbered 1 to 6, simultaneously. According to theoretical probability, how many of the rolls should Michael expect the sum to be 6 if he rolled them 108 times?

Question

Michael rolled two number cubes, numbered 1 to 6, simultaneously.  According to theoretical probability, how many of the rolls should Michael expect the sum to be 6 if he rolled them 108 times?

anonymous · Answer

sorry i suck at probability!

anonymous · Answer

me too:(

anonymous · Answer

do you think i would divide 6/108?

anonymous · Answer

i think u find all the possibilites that would make it 6, and then out of 36 (since that's the total number of sums.

anonymous · Answer

n=36
so do we have to get the score on the upperface of both the cube be 6

anonymous · Answer

1+5,2+4,3+3,4+2,5+1 (these are 5 possibilites)
(5/36)^108 ---> i think :D

zarkon · Answer

$$\frac{5}{36}\cdot 108=15$$

anonymous · Answer

@zarkon is perfect

anonymous · Answer

thank you!!!

anonymous · Answer

yeah i meant to multiplication sign. sorry! yeah that means i got it right too!

anonymous · Answer

welcome

anonymous · Answer

haha i gave all of you guys medals!

anonymous · Answer

now i will give u a medal

zarkon · Answer

this is binomial...the mean is $n\cdot p$

anonymous · Answer

zarkon's in the lead for medals :D

anonymous · Answer

Yeahhh!!!! haha medals for evryone:D