Question

FOR REDUCTION OF ORDER

(D^2+4)y=sinx

@TuringTest :)) i have the answer but i dont know how it came with it :)

Answer 1

well i can tell you how to do it

Answer 2

that's great! can you help me? please? :)

Answer 3

do you want complimentary or particular solution

Answer 4

both? and the general solution? :)))) please?

Answer 5

y complimentary =d^2=-4
d=+2i, -2i
hence Y complimentary =C1 cos2x+C2 Sin2x

Answer 6

Y particular = (Sinx)/(D^2 +4)
now the cofficient of x (that is with sin =1)
hence we put the square of the negative value of coffiecient of x in the variable D
hence it becomes
Sinx/(- (1^2)+4)
hence Y particular=Sinx/3

Answer 7

can you give me a detailed solution? like in integrating it? or what? does it need wronkian in reduction?

Answer 8

Lol its the solution and detailed one and the general solution is Yparticular + Y general

Answer 9

so you mean the reduction of order is a simplier method compared to variation? or it depends?

Answer 10

well i did the differential equations this way and i find it simple

Answer 11

u in which grade

Answer 12

2nd year college

Answer 13

im a first year college student though :D

Answer 14

hmm.. i thinkn you have k12 :)

Answer 15

so what's the steps that im going to put on my paper? :) first the yc then the yp immediately? and lastly the y?

Answer 16

yehh exactly :)

Answer 17

what is K12

Answer 18

woah. what a short process?

Answer 19

yehh i will be glad to help u in these type of questions :)_

Answer 20

hence we put the square of the negative value of coffiecient of x in the variable D hence it becomes ??? wat do u mean of that? can u clarify it with me?

Answer 21

like if its Sin 2x then the cofficient of x=2 and hence we would put the square that is 4 in this case and negative means i will add - to the square of the coffiecient .

Answer 22

but remember we can only do that when it is D^2

Answer 23

so i shall only follow the process that you gave to me?

Answer 24

yehh u should

Answer 25

Y particular = (Sinx)/(D^2 +4) now the cofficient of x (that is with sin =1) hence we put the square of the negative value of coffiecient of x in the variable D hence it becomes Sinx/(- (1^2)+4) hence Y particular=Sinx/3


so i will put this on my paper? lol

Answer 26

yp= sinx / (d^2+4)

Answer 27

Yparticular = (Sinx)/(D^2 +4) now the cofficient of x (that is with sin =1) hence we put the square of the negative value of coffiecient of x in the variable D^2 hence it becomes Sinx/(- (1^2)+4) hence Y particular=Sinx/3

Answer 28

now thats perfect

Answer 29

now the cofficient of x (that is with sin =1)???? this?

Answer 30

yehh

Answer 31

wat do u mean? is it constant? sin =1?

Answer 32

i mean if its sin3x then constant cofficient=3

Answer 33

ahh.. now i know! i get it. lol HAHA so if sin3x the it could sin3x/-3^2+4? i jst change 1 to 3

Answer 34

yayyy finally u got it :)

Answer 35

hmm.. so the short process of yours will give me high score? :))

Answer 36

yehhh :)

Answer 37

HAHA. thanks friend. i hope i can count on you next time :)

Answer 38

Lol probability is low though :D

Answer 39

HAHA.. lol :)

Answer 40

sorry, I need to review reduction of order...

Answer 41

hey turing test. i have a question. ahm. can wolfram able to answer laplace problems?

Answer 42

yes it can

Answer 43

http://www.wolframalpha.com/input/?i=laplace+inverse