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x^2/4 - 3x/2 = -5/4
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multiply each term by 4, then you can forget about the denominator and solve for x by factoring: x^2-6x=-10 x^2-6x+10=0 (x-1)(x-5)=0 x=1,x=5
how do you get 10?
i said u can forget about the denominator, but i'll write it again with the denominator
\[4(\frac{x^2}{4})-4(\frac{3x}{2})=4(\frac{-5}{4})\] \[x^2-6x=-10\]
x^2-6x+10=0 (x-1)(x-5)=0 x=1,5
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i see it, thank you and sorry for the inconvenience. thanks
you're welcome. no inconvenience
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