given cos theta=-1/5 , pi
use the pythag identitiy: cos^2 + sin^2 = 1
and since theta is in the 3rd quadrant, the sign of sin will be negative
what is theta though?
sin theta...
doesnt matter, you already know that value of cos regardless of theta
if we arrange the identity to solve for sin we get: cos^2 + sin^2 = 1 sin^2 = 1 - cos^2 sin = sqrt(1-cos^2) and since you already know cos, plug it in to determine sin
if the mathing method is a bit to abstract, we also have the option of simply drawing a circle and applying the trig definitions to it
sounds good.
|dw:1332861064537:dw|
cos = nextto/hyp so we apply the values given to the triangle about t sin = over/hyp ; in this case sqrt(10-1)/5 and since we are confined to an area in the region where sin is negative; just make sure the end result has a negative sign attached to it
umm, 5^2 = 25 ... not 10 :)
sin = sqrt(25-1)/5 would definnatly be a better value
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