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Mathematics 18 Online
OpenStudy (anonymous):

what is the x intercepts of f(x)=x^2+2 please provide steps if possible, thank you very much

OpenStudy (anonymous):

x intercept is where the graph crosses the x-axis, and that is where y = 0, right?

OpenStudy (anonymous):

i'm not sure :/ all i did was used the quadratic formula but i'm getting a negative under the square root

OpenStudy (anonymous):

yes, the answers are imaginary

OpenStudy (anonymous):

so there are no x intercepts

OpenStudy (anonymous):

on a graph the x intercept is will shape the parabola while the vertex = (0,2)

OpenStudy (anonymous):

not really... but if you have a good imagination, you can say that \[i \sqrt{2} , -i \sqrt{2}\] are where it crosses

OpenStudy (anonymous):

can you show me how did you did you do that?

OpenStudy (anonymous):

no, you will hit imaginary numbers later... i is the square root of -1 just show the work you did to show that the parabola doesn't cross the axis

OpenStudy (anonymous):

there are no real roots, only imaginary ones

OpenStudy (anonymous):

im not sure how to draw this parabola its suppose to look like this|dw:1332883453715:dw|

OpenStudy (anonymous):

if you have not worked with imaginary numbers yet, just stop at the negative square root and say it is impossible. You are right. And yes, the parabola is centered on the axis and slid up two units.

OpenStudy (anonymous):

yeah but the problem is how would i draw that if there's 11 units from the center to the top? i dont know far wide to draw it

OpenStudy (anonymous):

that's where you plot points (or a graphing calculator)

OpenStudy (anonymous):

you are better at this than you think... trust your instincts

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