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Definite Integral - need help with this one
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\[\int\limits_{1}^{5}(1-x) dx\]
I have to use the limits of sums
@amistre64 can you help me on this one? Thanks
\[\int\limits_{1}^{5}(1-x) dx = \sum_{x=1}^{5}(1-x) \Delta x\]
I know my delta x is 4/n but I am not sure how to find x I thought it was \[\frac{4i}{n}\]
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your x is the start of your interval + the subdivisions of the rest of it added up
x = 1 + 4i/n
then as n moves towards infinity your inteval is chopped up into infintesimal bits
try this; spose x moves from 2 to 12 how would you write up an equivalent part for x
2+6i/n but I am guessing
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think of it as \[I=[a,b]\]\[x=a+(b-a)\frac{i}{n}\]
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