can anyone help me with either of these two questions? i am posting a picture of them in this

Question

anonymous · Answer

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anonymous · Answer

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anonymous · Answer

You have two linear equations in cos and sin. Solve them first.

anonymous · Answer

first one solve 
$$3x-4y=-4$$
$$4x+3y=-3$$

anonymous · Answer

Multiply top equation by 3 and bottom one by 4, add. You will get an equation in cos(x) only. Then, you go solve for sin(x). Then, cot(x) is nothing but cos(x)/sin(x).

anonymous · Answer

get 
$$x=-\frac{24}{25},y=\frac{7}{25}$$ so cotangent is 
$$-\frac{24}{7}$$ if i am not mistaken

anonymous · Answer

second one locate 
$$\frac{13\pi}{2}$$ on the unit circle

anonymous · Answer

note that it is coterminal with 
$$\frac{\pi}{2}$$ and the coordinates of that point on the unit circle are (0,1) 
take  your answers from that point

anonymous · Answer

THANKS SO MUCH

anonymous · Answer

so i start at that coordinate and

anonymous · Answer

so what does the triangle look like? i know its 1 going straight up
but what/ how do i find out the other sides?

anonymous · Answer

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