This is using logarithms. I'm stuck on this problem 6^(x-3/4)=square root of 6 Please Help!
6^(1/2)=6^(x-3/4) x-3/4=1/2, solve for x
sqrt(6)=6^(1/2)
\[\ln 6^{x-3/4}= 6^{1/2}\] \[(x-3/4)\ln 6=(1/2)\ln 6\] \[x-3/4=1/2\] x=5/4
\[6^{x-3/4}=\sqrt{6}=6^{1/2}\implies x-3/4=1/2 \implies x=5/4\]
sorry for my ans. I miss ln on the right hand side but the other steps are ok
OMG Thank Ya'll Sooo Much!!!! I appreciate it! And its fine, its more than what I've done so far.
:D I am glad that I can give a helping hand to you.
Well thank you, I appreciate it! :)
Are you a college student? I am just interested.
haha yea I am
me2 and I am from Hong Kong. :D
Thats awesome, I'm from North America. I bet ya'll are A LOT smarter than we are! lol
maybe I am just a bit older than you. I am now Form 7, the last year in college. If I am lucky enough, I will be in the university next year.
Wow thats pretty good. i have a long ways until I get into a university. I'm barely finishing up my first year in a junior college this may.
oh, i see. Keep going!
I am! lol Even though its going to take forever to graduate. Good luck to you though!
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