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Find all zeros of the polynomial. P(x) = x^5 - 29x^3 - 58x^2 + x - 29.
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this is written correctly? there are no rational roots to help simplify it
Right, it can be divided with synthetic division by 29
remainder won't be 0
then factored by (x^2+1)^2, bit it needs to be reduced further
as pax said, 29 isn't a zero
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unless you made a typo
i reconstructed the original with your quotient, yes...i got that
x^5-29x^4+2x^3-58x^2+x-29
so x^2+1=0 x^2=-1 x= +/- i, i multiplicity 2, -i multiplicity 2, 29 are the zeros
awesome! thats what i got.
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