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f(a)=(7/(a-6))-(84/(a^2-36)) evaluate the limit where a approaches 6 f(a)=? please explain the steps
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lim(7(a+6)-84)/(a^2-36)=lim(7a-42)/(a^2-36)=lim7/(a+6)=7/12, ok ?
I don't think that's right
0/0 ?
limit a -> 6
are u mathtype and word 2003 ?
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lim (7/(a-6))-(84/(a^2-36)) =lim((7/(a-6))-(84/((a-6)(a+6))) =lim ((7(a+6)-84)/((a-6)(a+6))) =lim ((7a+42-84)/((a-6)(a+6))) =lim ((7a-42)/((a-6)(a+6))) =lim(7(a-6)/((a-6)(a+6))) =lim (7/(a+6)) =7/12
ok
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