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what mass of iron is needed to react completely with 32.0 of sulfur? (Fe+S-->FeS)
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atomic weight of sulphur=32 so, 1 mole iron is needed to react with 32 g of sulphur 1 mole iron=53.5 g of iron
iron forms iron sulphide when reacts with sulphur, Fe + S = FeS in this reaction 32 g of sulphur require 56 g of iron
yes it is 52 g of iron.... as for every one mole of sulphur we need one mole of iron
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in all these sums do by number of equivalence ..no need to balance reaction and others if sum is more difficult
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