Question

how to find nth derivative of sin x

Answer 1

- cos x.

Answer 2

y=sin(x)
y'(x)=cos(x)
y''(x)=-sin(x)
y'''(x)=-cos(x)
y''''(x)=sin(x), so at the 4th derivative, we're back to sin(x)

Answer 3

i want nth derivative ... bro

Answer 4

Yn for sin (ax+b) ???

Answer 5

sin ( n pie/2 + x )

Answer 6

No..thats not correct pavan

Answer 7

Explain why it is not

Answer 8

For nth derivative...if n is odd-
derivative would be - a^n( cos(ax+b))

and if n is even-
derivative would be a^n ( sin(ax+b))

Answer 9

The answer I said was for sin x.If you meant the nth derivative of Sin(ax+b),then you're right

Answer 10

well..yes in that case..you are right.