Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

how do I solve? kind of confused. Find the measures of each angle using the theorems. Picture shown below.

OpenStudy (anonymous):

OpenStudy (anonymous):

I know vertical angles are congruent, and that 1 and 4 and 2 and 3 will be supplementry.

OpenStudy (anonymous):

hmm... that looks impossible...

OpenStudy (anonymous):

1 and 3 have to be equal if these are straight lines

OpenStudy (anonymous):

what? waaaah. ;(

OpenStudy (anonymous):

oh, not wait, sorry, my bad

OpenStudy (anonymous):

well, they are vertical angles so I know they are congruent.

OpenStudy (anonymous):

I was thinking of if these lines had met at the center of the circle...

OpenStudy (anonymous):

Does 1/3 = 2/4? Geometry theorems are not exactly fresh in my memory

OpenStudy (anonymous):

referring to the the arcs captured by the angles

OpenStudy (radar):

It would be nice if the circumference or radius of the circle was given. What theorem does the problem want you to use (it says use theorem ??)

OpenStudy (anonymous):

4 and 2 equal 140 and 1 and 40 is what I came up with by making up a few theorems out of shear imagination and assumptions

OpenStudy (radar):

That would give you a sum of 140 + 140 + 40 +40 =360 that is consistent, but how did you come up with that? Lets hear your assumptions, and reveal the imaginations.

OpenStudy (anonymous):

well, alright, I really am not sure about anything I'll be saying from this point on, but I think it might make sense. also, (50+30)/2 = 40, so maybe that's some kind of a theorem. let's suppose arc1/arc3 = arc2/arc4 arc2 = 360-30-50-arc4 (280-arc4)/arc4=50/30 arc4=105 arc2=175 then, for the actual angles (1=x, 2=y) 175/50= x/y x=180-y 175/50=(180-y)/y y =140 x=40 Disclaimer : I cannot be held responsible for a wrong answer here :-P

OpenStudy (anonymous):

the answer was right! thank you.

OpenStudy (anonymous):

well I'll be damned! Ok, I won't be building bridges anytime soon with that kind of reasoning, but it's still nice to know that I got some good geometry instincts ;-)

OpenStudy (anonymous):

haha, true! thanks so much.... onto another problem that is distinctly the same. -__-

OpenStudy (radar):

Your intuition was great, deserve a medal for sure @m_charron2

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!