The floor of a shed has an area of 88 square feet. The floor is in the shape of a rectangle whose length is 5 feet less than twice the width. Find the length and the width of the floor of the shed. ??????
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OpenStudy (anonymous):
how do you find the area of a rectangle?
OpenStudy (anonymous):
l*w
OpenStudy (anonymous):
yes
and now how can you say what the length is here using only the width?
OpenStudy (anonymous):
what number is 5 less than twice another number?
use W for the other number
OpenStudy (anonymous):
88=2w+(l-5)
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OpenStudy (anonymous):
i mean times (l-5)
OpenStudy (anonymous):
close, but we need to get rid of the L...
what is L? only using W and numbers and +-*/ ?
OpenStudy (anonymous):
im not sure what your saying
OpenStudy (anonymous):
5 less than twice W
OpenStudy (anonymous):
how can you express that for algrebra?
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OpenStudy (anonymous):
2w-5
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
so that is the length
and Area = Width * Length so...
OpenStudy (anonymous):
you know the Area, we are using W for the width, and you know the Length
so plug them in and solve for W
OpenStudy (anonymous):
ok so 88=W*2W-5
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OpenStudy (anonymous):
yes, but be careful here... you need parentheses
OpenStudy (anonymous):
area = (Length)(Width)
OpenStudy (anonymous):
88 = W (2W - 5)
OpenStudy (anonymous):
ok distribute?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
2w^2 - 5w - 88 = 0
solve for W and remember that L = 2W - 5
OpenStudy (anonymous):
ok so then i get -11/2 and 8... well 11*8 equals 88 but the