Question

This one should be fun:

http://dl.dropbox.com/u/12189012/fact.html

Answer 1

2
137
577
22689565741

Answer 2

it's prime.... ;)

Answer 3

Where did you get those numbers from? And it's not a prime number.

Answer 4

are you actually serious about solving that....????

Answer 5

I use some algorithms online

Answer 6

I guess you're right: this website is not a serious place. :)

Answer 7

Your algorithms are wrong because the number ends in 7, yet you say that it's divisible by 2. :P

Answer 8

actually this is a nyc place but that no. is a bit too large to solve...

Answer 9

oh yea......so it should be only itself...

Answer 10

This number has only two factors.

Answer 11

yes.....got it

Answer 12

then they have to be 1 and itself and hence its prime...

Answer 13

I already said that the number is not prime!

Answer 14

then how can it have ONLY 2 factors.....1 and itself have to be compulsory factors....

Answer 15

With two factors, I obviously meant to state proper ones (and excluding 1).

Answer 16

Otherwise, the problem would've been trivial, no? ;P

Answer 17

with such a LARGE no. the problem can never be a trivial one.....

Answer 18

2158122193002952449690243008233157266924190689,
24058327474941875553768074062128402939746847713

Answer 19

I said that the problem would have been trivial if it had been a prime.

Answer 20

Zarkon, how did you do that? ;P

Answer 21

I wonder if you wrote a program.

Answer 22

I'm part machine.

Answer 23

so, how do we 'solve' this? o.O

Answer 24

i'm going to write a program to solve this :) and yes, should be fun :D

Answer 25

Not just any program, we need a very fast prime factorization algorithm is required.

If you are very confident about your algorithm , you may consider testing it here:www.spoj.pl/problems/FACT2/