if v(t)= 50 + ce^0.196t by putting different values of c what is the process of getting the values for v(t)?

Question

anonymous · Answer

we can also put random values for t

anonymous · Answer

all I want to know that how to solve e

anonymous · Answer

do we have to just puglin it's value 2.71828 ?

turingtest · Answer

I'm not sure I understand the question...
for e you just use the number 2.71828...
the value of c you have will change the shape of your graph, and each corresponds to a different integral curve

turingtest · Answer

all the different blue lines here (above ex 1) are the function v with different values of C
so the exact function depends on the value of C, which is found by applying the initial conditions (if there are any)

anonymous · Answer

at http://tutorial.math.lamar.edu/Classes/DE/Linear.aspx right after the example number 1 the author has sketched a graph, he claims that he made this graph by putting different values of c in v(t)=50+ce^-0.196t , for example if I want to put c=20 then how will I get the value?

turingtest · Answer

forgot to post the link http://tutorial.math.lamar.edu/Classes/DE/DirectionFields.aspx

turingtest · Answer

what value?
you get a function, not a single value

turingtest · Answer

put C=20 and you get
v(t)=50+20e^-0.196t
which is just a function of t

anonymous · Answer

yeah the value of the function "v(t)"

turingtest · Answer

at what time?

anonymous · Answer

v(t)=50+20e^-0.196t how to solve it? :|

anonymous · Answer

lets say 1

turingtest · Answer

it's solved, just plug in whatever value for t you need
if t is in minutes and you want the velocity at 5 min, then plug in t=5 and you get your answer

turingtest · Answer

let's say 1?

anonymous · Answer

I mean numerically or on calculator what value of e should I plug

anonymous · Answer

2.71828

turingtest · Answer

if we let C=20 and t=1 we have$$v(1)=50+20e^{-0.196}$$yes, if your calculator does not have e just put in however many digits you want for the number
2.718281828459045...

anonymous · Answer

at c = 20 & t=1 I get 50.4456365691809 whereas at c20 i should get 70 isn't?

anonymous · Answer

ooopps I am forgetting to add 50

anonymous · Answer

got it now

anonymous · Answer

thanks @TuringTest

turingtest · Answer

very welcome, as usual :D