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Find all points on the graph of the function f(x) = 2 sin x + sin^2 x at which the tangent line is horizontal.
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f'(x) = sin2x i know that much
quite not ..
try finding the deivative again...(for asker)
oh oh oh wait you're right hold up
i think it's better if you don't simplify f'(x)
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nah i just didn't apply the product rule for the first term so i just had that as 0 but now i have f'(x) = 2 cos x sin 2 x
I MEAN 2 cos x + sin 2 x
ok, that's it... set = 0 to find your horizontal tangents...
uh rusty on trig run me through it
ok. your derivative is set to zero: 2cosx + sin2x = 0
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|dw:1333128565642:dw| this is just the same but the derivative is not simplified... you can factor the left side of the equal sign...
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