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Mathematics 19 Online
OpenStudy (anonymous):

Find all points on the graph of the function f(x) = 2 sin x + sin^2 x at which the tangent line is horizontal.

OpenStudy (anonymous):

f'(x) = sin2x i know that much

OpenStudy (experimentx):

quite not ..

OpenStudy (anonymous):

try finding the deivative again...(for asker)

OpenStudy (anonymous):

oh oh oh wait you're right hold up

OpenStudy (anonymous):

i think it's better if you don't simplify f'(x)

OpenStudy (anonymous):

nah i just didn't apply the product rule for the first term so i just had that as 0 but now i have f'(x) = 2 cos x sin 2 x

OpenStudy (anonymous):

I MEAN 2 cos x + sin 2 x

OpenStudy (anonymous):

ok, that's it... set = 0 to find your horizontal tangents...

OpenStudy (anonymous):

uh rusty on trig run me through it

OpenStudy (anonymous):

ok. your derivative is set to zero: 2cosx + sin2x = 0

OpenStudy (anonymous):

|dw:1333128565642:dw| this is just the same but the derivative is not simplified... you can factor the left side of the equal sign...

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