Can someone help me find where this function is increasing. f(x)=x^3(x+8)^6 i need to the intervals. Do i take the derivative and set it equal to zero to get critical pts??

Question

inkyvoyd · Answer

Yes. To find where the function is increasing, take the derivative and solve for an inequality (f'(x) > 0).

anonymous · Answer

is there any way you can help me take the derivative and solve it i cant seem to figure it out?

inkyvoyd · Answer

is the equation (x^3)(x+8)^6=f(x)?

anonymous · Answer

yes

inkyvoyd · Answer

Ok, do you know the product rule?

anonymous · Answer

yes its der of x^3 times the second part plus der of second times first

anonymous · Answer

do i need to do the chain rule for (x+8)^6

inkyvoyd · Answer

$$[x^3][ (x+8)^6]$$

inkyvoyd · Answer

First use the product rule to calculate those two parts, then use the chain rule to calculate the second part. I think.

anonymous · Answer

this is as far as i got: $$(3x^2)(x+8)^6+(x^3)6(x+8)^5(1)$$ do you think that is correct in terms of being the derivative?

inkyvoyd · Answer

http://www.wolframalpha.com/input/?i=d%28%28x^3%29%28x%2B8%29^6%29%2Fdx Click "Show steps" for the answer.

anonymous · Answer

ok thank you!, is there a website that can help me in terms of setting it equal to zero and solving for the x value or values

inkyvoyd · Answer

That website does that too.