$$f(2x-3)=4x+1 \quad , \quad f(x+2)=?$$

Attempted:

I substituted 2x-3=t

so...

2x-3=t

$$x=\frac{t+3}{2}$$

Now $$f(t)=4\cdot \left(\frac{t+3}{2}\right)+1$$

f(t)=2t+7

now substitute t=x

f(x)=2x+7

but how to find f(x+2)=? ..I need a hind please.

Question

$$f(2x-3)=4x+1 \quad , \quad f(x+2)=?$$

Attempted:

I substituted 2x-3=t

so...

2x-3=t

$$x=\frac{t+3}{2}$$

Now $$f(t)=4\cdot \left(\frac{t+3}{2}\right)+1$$

f(t)=2t+7

now substitute t=x

f(x)=2x+7

but how to find f(x+2)=?  ..I need a hind please.

anonymous · Answer

i think you did most of the work already...
since f(x) = 2x + 7, then f(x+2) = 2(x+2) + 7... isn't it?

anonymous · Answer

agreed

anonymous · Answer

... thank you, anyway i prefer to show my work , so the people can help me easily.  There I was confused, I didn't know if I have to add +2 like this:  f(x+2)=(2x+7)+2   or as you did... thanks again. :D

anonymous · Answer

I know the result I'll be the same ... but I thought about other cases... in General ;)