Question

A grain silo is shown below.



What is the volume of grain that could completely fill this silo rounded to the nearest whole number? Use for pi.

34,597 ft3

11,532 ft3

35,669 ft3

2,146 ft3

Answer 1

\[\pi (8)^2(172)+\frac{1}{2}(\frac{4}{3})\pi (8)^3\]

Answer 2

What are you supposed to use for pi?

Answer 3

my answers are close to 34,597 and 35,669
(the answers above)

Answer 4

The silo volume is equal to the sum of the volume of a hemisphere and that of a cylinder.\[\frac{\frac{4}{3}\pi r^3}{2}+\pi r^2h=\frac{1}{3} \pi r^2 (3 h+2 r)\text{=}35655\]where r=8 and h=173

Answer 5

sweet i was close then thanks

Answer 6

35669 then.

Answer 7

35,669 ft3
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The silo is a right circular cylinder and a hemisphere.
Volume of Cylinder
===========
V = pi r^2 h
V = pi (8)^2 (172)
V =11 008 pi
Volume of Hemisphere
=============
Volume = (1/2) (4/3) pi (r)^3
Volume = (2/3) pi (8)^3
Volume = 1024 / 3 pi
Volume of Silo = 11 008 pi +( 1024 /3) pi =
(11 008 + 341 1/3) pi = 35 669.334 approx