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Mathematics 19 Online
OpenStudy (anonymous):

what do I get if I defferentiate xlnxlnx?

OpenStudy (anonymous):

\[\log^2(x)+2 \log(x) \]

OpenStudy (anonymous):

it is in ln: ln(lny)=xlnxlnx

OpenStudy (anonymous):

Is the following the expression you intended?\[x \log (x) \log (x) \]

OpenStudy (anonymous):

xln(x)ln(x)

OpenStudy (anonymous):

log is used here as the natural logarithm. So the answer is:\[\ln ^2(x)+2 \ln (x) \]

OpenStudy (anonymous):

ln(y)=(x)^xln(x), I want to see how it's defferentiated please, Robtobey!

OpenStudy (anonymous):

Product rule. The equation you give is really just xln^2(x). Do the product rule with lnx and x

OpenStudy (anonymous):

Yes, exactly. my problem is defferentiating ln^2(x). That is 1(ln^2(x) + ?

OpenStudy (anonymous):

d/dx of ln^2(x)= 2lnx*(1/x)

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

I need to integrate (arctg\[\sqrt{x}\] using integration by parts

OpenStudy (anonymous):

@satiranks A solution for the above integration is attached.

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