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Mathematics 18 Online
OpenStudy (anonymous):

derivative of: sqrt(x) - x using the first principal. Please show work. The answer should be 1/[2*sqrt(x)]-1 I cant get the minus 1!

OpenStudy (experimentx):

i guess you know how to find the derivate of x ... so just find for sqrt(x)

OpenStudy (anonymous):

f(x) = \[\sqrt{x} -x \]

OpenStudy (anonymous):

oh...so just do them one at a time?:| That actually makes a lot of sense. the problem is I have the equation in the "definition of the derivative formula" and its not simplifying down right.

OpenStudy (anonymous):

where you take the limit as h-->0

OpenStudy (experimentx):

lim dx->0 (sqrt(x+dx) - sqrt(x))/dx now sqrt(x+dx) = sqrt(x)*sqrt(1+dx/x) using binomial expansion, and removing higher terms --- close to linear expression we have: sqrt(x)(1+1/2*dx/x) or, lim dx->0 (sqrt(x)(1+1/2*dx/x) - sqrt(x))/dx or, lim dx->0 (1/2*dx/sqrt(x))/dx = 1/(2sqrt(x)) hence proved

OpenStudy (lgbasallote):

seems he wants the increment thingy...the limits

OpenStudy (anonymous):

@Ravus , are you asking to take the derivative using the definition? (limit definition of derivative)

OpenStudy (perl):

@experimentX how do you get this sqrt(x+dx) = sqrt(x)*sqrt(1+dx/x)

OpenStudy (anonymous):

@perl, nice avatar!

OpenStudy (perl):

hehe

OpenStudy (anonymous):

yes I want the "increment thingy"<<<thats exactally it! and yes dpalnc, I think it is the limit definition I mean.

OpenStudy (experimentx):

@perl .. take x common!

OpenStudy (perl):

huh?

OpenStudy (anonymous):

|dw:1333351654824:dw| plug it in to that...

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