Question

Find the smallest number such that
i) it leaves a remainder 2 when divided by 3;
ii) it leaves a remainder 3 when divided by 5;
iii) it leaves a remainder 5 when divided by 7.

Answer 1

i)5
ii)8

Answer 2

iii.)12

Answer 3

The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.

Answer 4

ah ok

Answer 5

LCM of 5,8,12 is the answer

Answer 6

Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.

Answer 7

Sorry for that. I have made a mistake

Answer 8

68= 3*22 +2
= 5*13 +3
= 7*9 + 5