Find the smallest number such that
i) it leaves a remainder 2 when divided by 3;
ii) it leaves a remainder 3 when divided by 5;
iii) it leaves a remainder 5 when divided by 7.

Question

Find the smallest number such that 
i) it leaves a remainder 2 when divided by 3; 
ii) it leaves a remainder 3 when divided by 5; 
iii) it leaves a remainder 5 when divided by 7.

anonymous · Answer

i)5
ii)8

anonymous · Answer

iii.)12

pythagoras123 · Answer

The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.

anonymous · Answer

ah ok

anonymous · Answer

LCM of 5,8,12 is the answer

pythagoras123 · Answer

Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.

anonymous · Answer

Sorry for that. I have made a mistake

hoblos · Answer

68= 3*22 +2
    = 5*13 +3
    = 7*9 + 5