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Mathematics 19 Online
OpenStudy (anonymous):

hhhhhhhhhh

OpenStudy (inkyvoyd):

Volume of cylinder minus volume of cube

OpenStudy (inkyvoyd):

Take the result of that, and divide by volume of cylinder again.

OpenStudy (anonymous):

I know how to do it, however I keep doing that and I get different numbers each time. Could you walk me through it?

OpenStudy (inkyvoyd):

ok, so we have (pi)*r^2*(h) for the cylinder, but h=2r+4

OpenStudy (anonymous):

ok

OpenStudy (inkyvoyd):

thus it becomes pi*(r^2)(2r+4)

OpenStudy (inkyvoyd):

that's the volume of the cylinder.

OpenStudy (anonymous):

makes sense

OpenStudy (inkyvoyd):

now a cube is x^3, where x is the length.

OpenStudy (anonymous):

x would be r√2

OpenStudy (inkyvoyd):

Now, here's the tricky part.

OpenStudy (inkyvoyd):

(r√2)^3=2(r^3)√2

OpenStudy (inkyvoyd):

{pi*(r^2)(2r+4)-2(r^3)√2} / [pi*(r^2)(2r+4)] Volume of cylinder

OpenStudy (inkyvoyd):

i.e. (Vcylinder-Vcube)/(Vcylinder)

OpenStudy (inkyvoyd):

Now, let me write that out, so I don't make a mistake :)

OpenStudy (anonymous):

okay : )

OpenStudy (anonymous):

your writing ran off the page. I can't see all of it.

OpenStudy (inkyvoyd):

This is really confusing; just write it on a piece of paper, it should really help

OpenStudy (inkyvoyd):

I canceled out the top and bottom of the Vcylinder to make 1, because it was really the fastest way to do it.

OpenStudy (anonymous):

ok one sec.

OpenStudy (inkyvoyd):

1-(2(r^3)√2))/(π∗r^2∗(2r+4)) Sorry, it got messed up

OpenStudy (inkyvoyd):

{pi*(r^2)(2r+4)-2(r^3)√2} / [pi*(r^2)(2r+4)] =1-(2(r^3)√2))/(π∗r^2∗(2r+4))

OpenStudy (amistre64):

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