Mathematics
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OpenStudy (anonymous):
hhhhhhhhhh
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OpenStudy (inkyvoyd):
Volume of cylinder minus volume of cube
OpenStudy (inkyvoyd):
Take the result of that, and divide by volume of cylinder again.
OpenStudy (anonymous):
I know how to do it, however I keep doing that and I get different numbers each time. Could you walk me through it?
OpenStudy (inkyvoyd):
ok, so we have (pi)*r^2*(h) for the cylinder, but h=2r+4
OpenStudy (anonymous):
ok
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OpenStudy (inkyvoyd):
thus it becomes pi*(r^2)(2r+4)
OpenStudy (inkyvoyd):
that's the volume of the cylinder.
OpenStudy (anonymous):
makes sense
OpenStudy (inkyvoyd):
now a cube is x^3, where x is the length.
OpenStudy (anonymous):
x would be r√2
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OpenStudy (inkyvoyd):
Now, here's the tricky part.
OpenStudy (inkyvoyd):
(r√2)^3=2(r^3)√2
OpenStudy (inkyvoyd):
{pi*(r^2)(2r+4)-2(r^3)√2} / [pi*(r^2)(2r+4)]
Volume of cylinder
OpenStudy (inkyvoyd):
i.e. (Vcylinder-Vcube)/(Vcylinder)
OpenStudy (inkyvoyd):
Now, let me write that out, so I don't make a mistake :)
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OpenStudy (anonymous):
okay : )
OpenStudy (anonymous):
your writing ran off the page. I can't see all of it.
OpenStudy (inkyvoyd):
This is really confusing; just write it on a piece of paper, it should really help
OpenStudy (inkyvoyd):
I canceled out the top and bottom of the Vcylinder to make 1, because it was really the fastest way to do it.
OpenStudy (anonymous):
ok one sec.
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OpenStudy (inkyvoyd):
1-(2(r^3)√2))/(π∗r^2∗(2r+4))
Sorry, it got messed up
OpenStudy (inkyvoyd):
{pi*(r^2)(2r+4)-2(r^3)√2} / [pi*(r^2)(2r+4)]
=1-(2(r^3)√2))/(π∗r^2∗(2r+4))
OpenStudy (amistre64):
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