Question

https://www.connexus.com/content/media/459431-3172011-13026-PM-25179049.png

someone please help? so confused

Answer 1

LOL :p

Answer 2

what do you have to do? simplify it?

Answer 3

yah

Answer 4

my equation writer is playing up

Answer 5

In order to solve this problem you need to know how to do the following:

1. Divide fractions
2. Divide exponents
3. Square root properties
4. Exponent properties

Which of the following do you not know?

Answer 6

\[\sqrt{9x ^{14}y ^{-2}}\]There is a start.

Answer 7

Another start \[3x ^{7}\sqrt{1/y ^{2}}\] Whats left to do? It can be further simplified.

Answer 8

You wrap it up.

Answer 9

the rules you need to know are:

\[\sqrt{x} = x^{\frac{1}{2}}\]
\[x^a \times x^b = x^{a+b}\]
\[\frac{1}{x^c} = x^{-c}\]which implies \[\frac{x^a}{x^b} = x^{a-b}\] finally:\[(x^a)^b =x^{ab}\]

Answer 10

using those rules you can group the powers of x and y together until it looks simpler

Answer 11

try not to be confused by the fact that i used x to express those rules, by that i meant it works for any number, so it works for y as well

Answer 12

To explain further what I started 63/7 = 9 That is where the 9 came from fractional division.

\[x ^{15}/x=x ^{15}/x ^{1}=x ^{(15-1)}=x ^{14}\]\[y ^{9}\over y ^{11}\]is the same as \[y ^{(9-11)}y ^{-2}\]