Question

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Answer 1

use the factorization method. it is easy and shortcut too...

Answer 2

since you have the quadratic equation use this formula...
\[\Large x_{1/2}\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
a=1 b=-6 c=-27

just substitute and there you go...

Answer 3

i hope you know this method.

Answer 4

assume it factors:

(z+a)(z+b) = z^2 -6z -27 = 0

expand and compare

z^2 +(a+b)z + ab = z^2 -6z -27

Answer 5

a+b = -6
ab = -27

if it plays nice then we need to find factors of -27 that add up to 6

Answer 6

\[\large x ^{2}+3x-9x-27=0\]\[\large x(x+3)-9(x+3)=0\]\[\large (x+3)(x-9)=0\]now separately call them equal to zero.
good luck

Answer 7

I got it thanks everyone!

Answer 8

cool ;)

Answer 9

ever welcome. :D