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find all the critical points and then use the first derivative test to determine local maxima and minima check your answer by graphing f(x) = 3x^4 - 4x^3 + 6
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y intercepts = set x to zero x intercepts = set y to zero Take the derivative and set it equal to zero to find the critical points and take that point and plug it into the second derivative. If the second derivative = negative, then it is a max and if it is positive, then it is a min.
Is this correct
That looks correct, you just didn't plug the values you came up with at each step into the original equation to get the y coordinate, but the graph looks good and so does the work aside from that.
Thanks!!!
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