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If 2x^2 + x = 6, then which of the following could be the value of 2x^2 – x?
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\[\LARGE 2x^2+x-6=0 \quad use \quad x_{1/2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] since it's quadratic equation..
a=2 b=1 c=-6
\[\LARGE x_1=-2 \quad ,\quad x_2=\frac32\]
now substitute the values into the second equation... and find out what the solutions are... (If that's what is required...)
is it 4 ?
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if you substitute x=3/2 you'll get 3 if you substitute x=-2 you'll get...10
\[\LARGE 2\cdot \left(\frac32\right)^2-\frac32\] continue... and do the same with the second one too.. ;)
ooo
I got it, great thanks! :D
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