What is the length of the transverse axis?

(y-2)^2/(16) - (x+1)^2/(144) =1

Question

What is the length of the transverse axis?

(y-2)^2/(16) - (x+1)^2/(144) =1

amistre64 · Answer

which ones transverse?

amistre64 · Answer

-x^2 never can equal a +1  so the only axis we cross is the y axis; so if we double the sqrt of the denom under y that should do it

anonymous · Answer

so you take y-2^2 and 144 and do what

amistre64 · Answer

the 144 is under the x stuff so i dont think its gonna be important; but that might be the althimerz talking

16 is under the y spot.

sqrt(16) = 4 ; this should be half the distance we want, so double it

anonymous · Answer

I'm confused the square root of 16 is 4 but you want me to double it? so would it be 4(4) or 4(2) making 8?

amistre64 · Answer

4 doubled is 8