Question

2x^2 + x + 7 = 0

Answer 1

hint ...

use the quadratic formula...
\[\Large x_{1/2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

a=2 b=1 c=7 substitute !

Answer 2

-16/55(x+1/4)^2=1
2(x+1/4)^2+55/8=0

Answer 3

\[2x^2 + x + 7 = 0\]
\[x=\frac{-1\pm\sqrt{1-4\times 2\times 7}}{2\times2}\]will get two complex zeros