Question

Solve for x using properties of logarithms, 5^(x-1)=2^(2x+1)

Answer 1

\[\log_{5/4} 10\]

Answer 2

\[5^{x-1}=2^{2x+1}\]
Take log on both sides
\[log5^{x-1}=log2^{2x+1}\]BY\[loga^{b}=bloga\]
\[(x-1)log5=(2x+1)log2\]
Can you solve it from here?

Answer 3

I've gone that far, do I distribute?