Question

the future of my high school career is dependent upon these questions...
not really but ya know

1. 7^0
2. 2^-2
3. 2^-4•18^0
4. (2•5)^-2
5. 3^0•10^-4
6. a^-4
7. 3a^2b^-1

SAVE MEH

Answer 1

1
1/4 = 0.25
1/16 =
4/25 =
1/10000
1/a^4
3a^2/b

Answer 2

First you need to know (i)a^0 = 1, and (ii) a^(-n) = 1/(a^n)

then from (i) , you can solve 1.

for 2, put a =2 and n=2 into a^(-n) = 1/(a^n)

for 3, 2^-4•18^0 =[ 1/(2^4) ] (1)

for 4, (2•5)^-2 = 10^-2 = 1/(10^2) = 1/100

for 5, 3^0•10^-4 = 1 (10^-4) = see experimentX 's answer

for 6, put n = 4 into a^(-n) = 1/(a^n)

for 7, 3a^2b^-1 = 3 (a^2) / b (same as experimentX 's answer)

Well. experimentX saved you :P

Answer 3

thanks for explanation

Answer 4

lol i seem like copying your answers ..

Answer 5

still i you saved me ... i got complaints for not explaining properly.

Answer 6

Nah.. next time , save yourself, you can do it !

Answer 7

yeah ... sure i hope so.. lol