Question

critical point of 4x+4sin(x)

Answer 1

Derivative set equal to zero.

Answer 2

4 +4cos(x) =0
cos(x) = -1
x= (2n-1)Pi
n= 1,2,......n

Answer 3

i got zero when i did that but its online homework and its not accepting it

Answer 4

differentiating

= 4 + 4 cos x
at a critical point
4 + 4 cos x = 0
cos x = -1
x is what myko said

Answer 5

try puting\[(2n-1)\pi\]

Answer 6

in degrees x = -180, - 540 and so on

Answer 7

or plus x = 180, 540

Answer 8

inflection point would be the second derivative equal to zero

Answer 9

Answer would be Pi/2

Answer 10

Cos(x)=-1 X would be 180 degrees

Answer 11

for the inflection point?

Answer 12

Second derivative set equal to zero and solve

Answer 13

is the second derivative -4sin(x)

Answer 14

?

Answer 15

Yes, that's correct.

Answer 16

is the critical point 0?

Answer 17

Yes that's it