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Can someone help me with solving an equation in logarithmic form?
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I think you rewrite it in exponential form or something. But the method is hard to ascertain if you won't give an example.
\[\log_{2} \sqrt[3]{1/4} \]
you can rewrite this as \[\frac{1}{3}\log_{2}\frac{1}{4}\]
2 to what power equals 1/4?
that is the power rule of exponents btw. a logarithm is an exponent
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What did you get for the answer?
do you know what power you need to raise 2 to to get 1/4? 2^x=1/4 x=?
no
\[2^{-2}=\frac{1}{4}\]
\[\frac{1}{3}\log_{2}\frac{1}{4}=\frac{1}{3}(-2)=\frac{-2}{3}\]
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okay I get it now. thank you.
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