Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Calculus Help!! Find the fifth degree Taylor polynomial approximation T _{5}(x) centered at a=0 to the function f(x)=cos(x);f(x)=sin(x);f(x)=e^{x}

OpenStudy (anonymous):

\[T _{5}(x)\]

OpenStudy (anonymous):

f(x)=cos(x) f(x)=sin(x) \[f(x)=e ^{x}\]

OpenStudy (anonymous):

i tried put 1,0,1 and it is not correct!!

OpenStudy (anonymous):

i tried to put x^8/8!,x^9/9!,x^4/4! and it is not correct either!!

OpenStudy (anonymous):

for cos(x),i put 1-x^2/2!+x^4/4!-x^6/6! and it is wrong

OpenStudy (anonymous):

should i put one more term?

OpenStudy (anonymous):

there sould be 6 term..

OpenStudy (anonymous):

when should i put 6 terms and when should i put 5 terms and when should i put 4 terms?

OpenStudy (anonymous):

is it because it is an even power function?

OpenStudy (anonymous):

degree means how many derivation you need to have, so in your case 5 dervative plus f(x)

OpenStudy (anonymous):

Thanks a lot!!

OpenStudy (anonymous):

but how come for sin(x) ,it is x-x^3/3!+x^5/5!-x^7/7!

OpenStudy (anonymous):

OpenStudy (anonymous):

Thank you!!

OpenStudy (anonymous):

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

i am sorry.can you reattach it.it is kind of small that i can't really see==

OpenStudy (anonymous):

OpenStudy (anonymous):

way better now!!thanks!!

OpenStudy (anonymous):

now you can solve for cosx right

OpenStudy (anonymous):

yea.I got it!!Thanks a lot!!

OpenStudy (anonymous):

you can check your solution here, look at trigonometric func.. http://en.wikipedia.org/wiki/Taylor_series

OpenStudy (anonymous):

Thank you so much!! you are awesome=))

OpenStudy (anonymous):

np (:

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!