Question

What is the % of alcohol in patient's body?
The alcohol content in a 12oz beer is 5%. Patients weight is 150lbs.
What chemical reaction took place in patients body?
What substance is produced by liver?

Answer 1

There isn't enough info here. One beer? Two beer? Three beer? Floor? The rest of your questions I can't answer unfortunately. My friends google and wiki would be glad to help though.

Answer 2

shamalamadingdong, your friend in google and wiki?

Answer 3

It was a joke. I'm a jokester. I was implying that pineapple use Google and wiki to find the answer.

Answer 4

oh lol ur funny

Answer 5

The answer depends on what resources they want you to use. If they want the % of alcohol by weight(which seems likely considering the phrasing), we can calculate how much the alcohol weighs, and divide it by the weight of the patient.

if 5% of the 12oz beer is EtOH, than .6 fl oz was consumed. The density of EtOH is .8 ounces per fluid ounce, so .48 ounces, or .03 lbs, were consumed(.8 x .6 / 16). The quick answer is .03 / (150 + .72(weight of the person + beer without the EtOH)) -> 2e-4, or .02%.

For the BAC, you would use the Widmark Formula
http://www.seattle-duiattorney.com/dui/widmark-equation.php
that site has a lovely walkthrough already posted, just solve for BAC, and use time = 0.