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Find the trigonometric form for (√3 + i)(1 + i).
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is this your question.. \[(\sqrt{3}+i)(1+i)\]
no he's asking for the cis form
yesss
I know what he's asking..
\[(\sqrt{3}+i)(1+i)=\sqrt{3}-1+(\sqrt{3}+1)i\]
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im trying to get it to a squared + b squared form , so i could put it in trigonometric form .
I didnot finish yet..
\[|z|=r=\sqrt{x^2+y^2}\]
\[x=\sqrt{3}-1\quad y=\sqrt{3}+1\]
\[x^2=3-2\sqrt{3}+1\quad y^2=3+2\sqrt{3}+1\]
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\[x^2+y^2=8\] \[|z|=r=\sqrt{8}=2\sqrt{2}\]
\[\theta=\tan^{-1} \frac yx\]
\[\frac yx=2+\sqrt{3}\] \[\theta=\tan^{-1}( 2+\sqrt{3})=75\]
\[z=rcis \theta\]
\[z=2\sqrt{2}cis75\]
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or \[z=2\sqrt{2}cis \frac {\pi}{4}\]
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