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Let F(x)=int_{0}^{x}e^(-3t^4) dt Find the MacLaurin polynomial of degree 5 for F(x). Use this polynomial to estimate the value of int_{0}^{0.11}e^(-3x^4) dx
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\[F(x)=\int\limits_{0}^{x}e^(-3t^4) dt\]
i put 1-3x^4+3x^8/2!-3x^12/3!+3x^16/4! and it is not correct
\[\int\limits_{0}^{0.11}e^(-3x^4) dx\]
First let \[ h(x) = e^{-3 x^4} \] The MacLaurin polynmoial of Degree 4 of h at zero is \[1- 3 x^4\] Now the Maclaurin polynomial of degree 5 is \[ g(x)=\int_0^x (1-3 t^4) dt = x - \frac {3 x^5} 5 \] and \[ g[.11] = .10999\]
i put 0.10999 and it is not correct
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Give 4 or 5 significant digits
they are correct!!thanks!!
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