Question

I have 2 derivatives that i got wrong on my homework and i want help to solve them.

First is
find dy/dx if x^2*y + 4*4throot y = xy

second is -7t^3 + 3/(t^3) - 3 / (3rdroot t)- And i need to do this without the quotient rule.

Answer 1

Do you have the work that you used to get your previous answers?

Answer 2

\[F(x,y)=x ^{2}y +4\sqrt[4]{y} -xy = 0\]
\[dy/dx = - F _{x}(x)/F _{y}\]
so find it by implicit diferentiation

Answer 3

i don't have my steps that i did but i can show you the answers i got.

1st one was (1y --2xy-y ^(1/4))/(x^2 + 4(1/4y)^(-3/4) - x)


answer to second one i got -21t^2 + 1/3 (3t)^(-2/3) + 1/3(3t)^(-4/3)

Answer 4

x^2*dy/dx + 2xy + 4*1/4 y^(-3/4)*dy/dx = x dy/dx + y

solve for dy/dx

Answer 5

is this revised answer for my first problem correct?
(y - 2xy)/(x^2 + y ^(-3/4) - x)

Answer 6

x^2*dy/dx +dy/dx* y^9-3/4) - x (dy/dx = y - 2xy

yup - thats correct