Question

i think this question has to do with logarithms:
8-3^x=-1
does anyone know how to solve it?

Answer 1

How about add 3^x to both sides of the equation to get
8= -1+3^x
now add 1 to both sides:
8+1 = -1+1+3^x or 3^x= 9

The equation says "3 to some power equals 9"
So your first thought might (should?) be, write 9 as 3 to some power.
3^x= 3^2
so it looks like x=2.

Try x=2 in the original equation: 8 =? -1+ 3^2
-1+9= 8 yes. it works.