Question

How many grams of C02 will be produced from the combustion of 28.06g of C4H10 in the presence of 16.0g of 02 if the reaction yield is 95.0% 2C4H10 + 9O2 -> 8CO2 + 10 H2O

Answer 1

here, limiting reagent is O2
in the balanced equation, that will be 13 O2
so, 416 gm O2 produces 352 gm CO2
16 gm O2 produces 13.54 gm CO2
but yield is 95%
so, actual yield= 12.86 gm