Question

log2(9)+log2(x+3)=3

Answer 1

welcome back :)

Answer 2

\[\log_{2} 9 +\log_{2} (x+3) =3\]\[\log_{2} [9 (x+3)] =3\]\[\log_{2} [9 (x+3)] =\log_{2} 2^3\]
I think you can do it from here?

Answer 3

Note that \[\log_{2}2 =1 ;\]\[\log_{2} 2^3 =3 \log_{2} 2 = 3\]

Answer 4

from where did we got the second 2?

Answer 5

Nah...? Wait is my first step correct? I mean is that your question

Answer 6

*wait!

Answer 7

k :)

Answer 8

that was the log 2

Answer 9

is that your question:
\[\log_{2}9 +\log_{2}(x+3) = 3\]

Answer 10

yes

Answer 11

Consider the right side (RS) first
RS = 3 = 3log2 / log2 <- agree?

Answer 12

log2(9)+log2(X+3)=3
=>9(X+3)=2^3
=>9X+27=8
=>9X=-19
=>X=-19/9
for log to be defined
X>-3
here -19/9>-3 hence this has X=-19/9 root....

Answer 13

do mean 3 numbers?

Answer 14

3 is the number on the right of the equation
We are now considering the right side only

Answer 15

so, do we add log2 or take off log2

Answer 16

on the right side

Answer 17

I like to do logarithms like this. \[\log_{2}(9) + \log_{2} (x+3) = 3\]\[\log_{2}(9x+27) = 3\]\[2^{3} = 9x + 27\]\[x = 19/9\]

Answer 18

Got it?