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How do I solve sin^2 x = -2cos x?
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change sin^x in to cos x, you will have quadratic equation in cos x
Remember, sin^2 x+cos^2 x=1
solve the above equation that I gave you for sin^2 x, substitute, and do as experimentX has instructed.
sinx^2+cosx^2=1 \[\sin x =\sqrt{1-\cos^2}\] then u can easily solve it
So \[\sin ^{2}x=1-\cos ^{2}x\]? And then I replace sin^2x with that?
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Yes
So I wind up with cos^2 x – 2cos x – 1 = 0 and factor it as (cos x – 1)(cos x + 1) then solve?
No, it doesn't factor that way.
Add two to both sides to get cos^2 x-2cos x+1=2 then take the square root of both sides (cos x-1)=plus minus (sqrt 2)
Ah! So confusing.....thank you for you help...I appreciate it
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Also can be left as cosx(cosx-2) =1
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