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Mathematics 21 Online
OpenStudy (anonymous):

What is the completely simplified answer of ( (√19600x^8 y^-4/35)^2(√324x^13 y^12 z^-14/√24x^-3 y^-4 z^16)/(45x^3 Y^16 √z/√81x^4 y.z^3)^2)^-2 .((3xy^2)^2)/ ((x^2 .y^3 .Z^4)^-2)^-3: https://docs.google.com/viewer?a=v&pid=sites&srcid=ZGVmYXVsdGRvbWFpbnxuc3RyaWNrbGFuZGtlYWxpbmd8Z3g6MjIwZWI3Y2RjMWM4NDFhYw

OpenStudy (anonymous):

Tedious but simple. Just use your exponent rules.

OpenStudy (anonymous):

a little more help please

OpenStudy (anonymous):

Which part do you need help with?

OpenStudy (anonymous):

like the part with the square rooting

OpenStudy (anonymous):

A square root is simply an exponent of 1/2. So: \[\sqrt{x}^3 = (x^{1/2})^3 = x^{3/2}\]

OpenStudy (anonymous):

oh ok thanks for your help!

OpenStudy (anonymous):

Any more questions with exponents?

OpenStudy (anonymous):

him maybe do i just apply the G.E.M.S rule for this as well?

OpenStudy (anonymous):

Sorry I am not familiar with the GEMS rule. Care to explain what it is?

OpenStudy (anonymous):

ok Gems is like a rule to do for any problem it stands for Grouping Exponets Multiplication/division Subtraction/addition so would i apply that rule in this situation?

OpenStudy (anonymous):

Ah so that is a new abbreviation for the Order of Operations. But YES definitely use that :)

OpenStudy (anonymous):

oh ok thank you for the help!

OpenStudy (anonymous):

You will soon enough learn how ever, that since exponents are just like multiplication, so you will be able to do them at the same time.

OpenStudy (anonymous):

so when i have an exponent for example two is that the same as X^2= x.x

OpenStudy (anonymous):

Yup.

OpenStudy (anonymous):

ok that is all i need for now thanks again!

OpenStudy (anonymous):

No problem!

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