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Find the eigenvalues and eigenvectors of the following matrix 3 5 3 0 4 6 0 0 1
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\[C=\left(\begin{array}{ccc}3&5&3\\0&4&6\\0&0&1\end{array}\right)\]\[\left| C-\lambda I \right|=0\]solve for λ and you will get the eigenvalues
will it be like ? (3-lambda) 5 3 0 (4-lambda) 6 0 0 (1-lambda)
what do i do after that ?
find the determinant, set it to 0 and solve for lambda
that part is confusing me, could you explain please?
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do we have to find the eigen vector for each eigenvalue we get?
you know how to find the determinant of 3 x 3 matrices right ?
yes
yes, you need to find the eigenvectors for each eigenvalue
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